2n+8=4(n+2)-2n

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Solution for 2n+8=4(n+2)-2n equation: 



2n+8=4(n+2)-2n

We move all terms to the left:

2n+8-(4(n+2)-2n)=0



We calculate terms in parentheses: -(4(n+2)-2n), so:

4(n+2)-2n

We add all the numbers together, and all the variables

-2n+4(n+2)

We multiply parentheses

-2n+4n+8

We add all the numbers together, and all the variables

2n+8

Back to the equation:

-(2n+8)



We get rid of parentheses

2n-2n-8+8=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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