2n-2(2n-2)=5(-2n+9)-9

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Solution for 2n-2(2n-2)=5(-2n+9)-9 equation: 



2n-2(2n-2)=5(-2n+9)-9

We move all terms to the left:

2n-2(2n-2)-(5(-2n+9)-9)=0

We multiply parentheses

2n-4n-(5(-2n+9)-9)+4=0



We calculate terms in parentheses: -(5(-2n+9)-9), so:

5(-2n+9)-9

We multiply parentheses

-10n+45-9

We add all the numbers together, and all the variables

-10n+36

Back to the equation:

-(-10n+36)



We add all the numbers together, and all the variables

-2n-(-10n+36)+4=0

We get rid of parentheses

-2n+10n-36+4=0

We add all the numbers together, and all the variables

8n-32=0

We move all terms containing n to the left, all other terms to the right

8n=32

n=32/8

n=4

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