2n-2(4n+5)=-6(n-3)

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Solution for 2n-2(4n+5)=-6(n-3) equation: 



2n-2(4n+5)=-6(n-3)

We move all terms to the left:

2n-2(4n+5)-(-6(n-3))=0

We multiply parentheses

2n-8n-(-6(n-3))-10=0



We calculate terms in parentheses: -(-6(n-3)), so:

-6(n-3)

We multiply parentheses

-6n+18

Back to the equation:

-(-6n+18)



We add all the numbers together, and all the variables

-6n-(-6n+18)-10=0

We get rid of parentheses

-6n+6n-18-10=0

We add all the numbers together, and all the variables

-28!=0

There is no solution for this equation

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