2n-32=-8(n-2)+2n

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Solution for 2n-32=-8(n-2)+2n equation: 



2n-32=-8(n-2)+2n

We move all terms to the left:

2n-32-(-8(n-2)+2n)=0



We calculate terms in parentheses: -(-8(n-2)+2n), so:

-8(n-2)+2n

We add all the numbers together, and all the variables

2n-8(n-2)

We multiply parentheses

2n-8n+16

We add all the numbers together, and all the variables

-6n+16

Back to the equation:

-(-6n+16)



We get rid of parentheses

2n+6n-16-32=0

We add all the numbers together, and all the variables

8n-48=0

We move all terms containing n to the left, all other terms to the right

8n=48

n=48/8

n=6

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