2n-3=2(6-n)+7n

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Solution for 2n-3=2(6-n)+7n equation: 



2n-3=2(6-n)+7n

We move all terms to the left:

2n-3-(2(6-n)+7n)=0

We add all the numbers together, and all the variables

2n-(2(-1n+6)+7n)-3=0



We calculate terms in parentheses: -(2(-1n+6)+7n), so:

2(-1n+6)+7n

We add all the numbers together, and all the variables

7n+2(-1n+6)

We multiply parentheses

7n-2n+12

We add all the numbers together, and all the variables

5n+12

Back to the equation:

-(5n+12)



We get rid of parentheses

2n-5n-12-3=0

We add all the numbers together, and all the variables

-3n-15=0

We move all terms containing n to the left, all other terms to the right

-3n=15

n=15/-3

n=-5

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