2n-4-n=3(n+2)

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Solution for 2n-4-n=3(n+2) equation:



2n-4-n=3(n+2)
We move all terms to the left:
2n-4-n-(3(n+2))=0
We add all the numbers together, and all the variables
n-(3(n+2))-4=0
We calculate terms in parentheses: -(3(n+2)), so:
3(n+2)
We multiply parentheses
3n+6
Back to the equation:
-(3n+6)
We get rid of parentheses
n-3n-6-4=0
We add all the numbers together, and all the variables
-2n-10=0
We move all terms containing n to the left, all other terms to the right
-2n=10
n=10/-2
n=-5

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