2n-5(n-7)=6(n-4)-4

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Solution for 2n-5(n-7)=6(n-4)-4 equation: 



2n-5(n-7)=6(n-4)-4

We move all terms to the left:

2n-5(n-7)-(6(n-4)-4)=0

We multiply parentheses

2n-5n-(6(n-4)-4)+35=0



We calculate terms in parentheses: -(6(n-4)-4), so:

6(n-4)-4

We multiply parentheses

6n-24-4

We add all the numbers together, and all the variables

6n-28

Back to the equation:

-(6n-28)



We add all the numbers together, and all the variables

-3n-(6n-28)+35=0

We get rid of parentheses

-3n-6n+28+35=0

We add all the numbers together, and all the variables

-9n+63=0

We move all terms containing n to the left, all other terms to the right

-9n=-63

n=-63/-9

n=+7

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