2n-5=2(4n+3)+1

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Solution for 2n-5=2(4n+3)+1 equation: 



2n-5=2(4n+3)+1

We move all terms to the left:

2n-5-(2(4n+3)+1)=0



We calculate terms in parentheses: -(2(4n+3)+1), so:

2(4n+3)+1

We multiply parentheses

8n+6+1

We add all the numbers together, and all the variables

8n+7

Back to the equation:

-(8n+7)



We get rid of parentheses

2n-8n-7-5=0

We add all the numbers together, and all the variables

-6n-12=0

We move all terms containing n to the left, all other terms to the right

-6n=12

n=12/-6

n=-2

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