2n-6(2+3n)=20

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Solution for 2n-6(2+3n)=20 equation: 



2n-6(2+3n)=20

We move all terms to the left:

2n-6(2+3n)-(20)=0

We add all the numbers together, and all the variables

2n-6(3n+2)-20=0

We multiply parentheses

2n-18n-12-20=0

We add all the numbers together, and all the variables

-16n-32=0

We move all terms containing n to the left, all other terms to the right

-16n=32

n=32/-16

n=-2

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