2n-6=2(n+2)-10

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Solution for 2n-6=2(n+2)-10 equation: 



2n-6=2(n+2)-10

We move all terms to the left:

2n-6-(2(n+2)-10)=0



We calculate terms in parentheses: -(2(n+2)-10), so:

2(n+2)-10

We multiply parentheses

2n+4-10

We add all the numbers together, and all the variables

2n-6

Back to the equation:

-(2n-6)



We get rid of parentheses

2n-2n+6-6=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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