2n-9(10-2n)=5(n+3)

Solution for 2n-9(10-2n)=5(n+3) equation:

2n-9(10-2n)=5(n+3)

We move all terms to the left:

2n-9(10-2n)-(5(n+3))=0

We add all the numbers together, and all the variables

2n-9(-2n+10)-(5(n+3))=0

We multiply parentheses

2n+18n-(5(n+3))-90=0


We calculate terms in parentheses: -(5(n+3)), so:

5(n+3)

We multiply parentheses

5n+15

Back to the equation:

-(5n+15)


We add all the numbers together, and all the variables

20n-(5n+15)-90=0

We get rid of parentheses

20n-5n-15-90=0

We add all the numbers together, and all the variables

15n-105=0

We move all terms containing n to the left, all other terms to the right

15n=105

n=105/15

n=7