2n-9=3(n-2)

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Solution for 2n-9=3(n-2) equation: 



2n-9=3(n-2)

We move all terms to the left:

2n-9-(3(n-2))=0



We calculate terms in parentheses: -(3(n-2)), so:

3(n-2)

We multiply parentheses

3n-6

Back to the equation:

-(3n-6)



We get rid of parentheses

2n-3n+6-9=0

We add all the numbers together, and all the variables

-1n-3=0

We move all terms containing n to the left, all other terms to the right

-n=3

n=3/-1

n=-3

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