2n/5=1/3(2m-12)

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Solution for 2n/5=1/3(2m-12) equation: 


x in (-oo:+oo)

(2*n)/5 = (1/3)*(2*m-12) // - (1/3)*(2*m-12)

(2*n)/5-((1/3)*(2*m-12)) = 0

(-1/3)*(2*m-12)+(2*n)/5 = 0

(2*n)/5-1/3*(2*m-12) = 0

(-1/3*5*(2*m-12))/5+(2*n)/5 = 0

2*n-1/3*5*(2*m-12) = 0

2*n-10/3*m+20 = 0

(2*n-10/3*m+20)/5 = 0

(2*n-10/3*m+20)/5 = 0 // * 5

2*n-10/3*m+20 = 0

x belongs to the empty set

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