2n2+5n-1375=0

Solution for 2n2+5n-1375=0 equation:

2n^2+5n-1375=0

a = 2; b = 5; c = -1375;
Δ = b2-4ac
Δ = 52-4·2·(-1375)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-105}{2*2}=\frac{-110}{4}
=-27+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+105}{2*2}=\frac{100}{4}
=25
$