2n2+7n-5=2n2-3n+10

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Solution for 2n2+7n-5=2n2-3n+10 equation: 



2n^2+7n-5=2n^2-3n+10

We move all terms to the left:

2n^2+7n-5-(2n^2-3n+10)=0

We get rid of parentheses

2n^2-2n^2+7n+3n-10-5=0

We add all the numbers together, and all the variables

10n-15=0

We move all terms containing n to the left, all other terms to the right

10n=15

n=15/10

n=1+1/2

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