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2n^2-18n-224=0
a = 2; b = -18; c = -224;
Δ = b2-4ac
Δ = -182-4·2·(-224)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-46}{2*2}=\frac{-28}{4} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+46}{2*2}=\frac{64}{4} =16 $
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