2n2-30=-7n

Solution for 2n2-30=-7n equation:

2n^2-30=-7n

We move all terms to the left:

2n^2-30-(-7n)=0

We get rid of parentheses

2n^2+7n-30=0

a = 2; b = 7; c = -30;
Δ = b2-4ac
Δ = 72-4·2·(-30)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*2}=\frac{-24}{4}
=-6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*2}=\frac{10}{4}
=2+1/2
$