2n2-7n-5=2n2-3n+10

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Solution for 2n2-7n-5=2n2-3n+10 equation: 



2n^2-7n-5=2n^2-3n+10

We move all terms to the left:

2n^2-7n-5-(2n^2-3n+10)=0

We get rid of parentheses

2n^2-2n^2-7n+3n-10-5=0

We add all the numbers together, and all the variables

-4n-15=0

We move all terms containing n to the left, all other terms to the right

-4n=15

n=15/-4

n=-3+3/4

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