2n2-95=-9n

Solution for 2n2-95=-9n equation:

2n^2-95=-9n

We move all terms to the left:

2n^2-95-(-9n)=0

We get rid of parentheses

2n^2+9n-95=0

a = 2; b = 9; c = -95;
Δ = b2-4ac
Δ = 92-4·2·(-95)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-29}{2*2}=\frac{-38}{4}
=-9+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+29}{2*2}=\frac{20}{4}
=5
$