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2n^2=11n^2-6n^2
We move all terms to the left:
2n^2-(11n^2-6n^2)=0
We get rid of parentheses
2n^2-11n^2+6n^2=0
We add all the numbers together, and all the variables
-3n^2=0
a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$n=\frac{-b}{2a}=\frac{0}{-6}=0$
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