2n=3(n+4)+15

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Solution for 2n=3(n+4)+15 equation: 



2n=3(n+4)+15

We move all terms to the left:

2n-(3(n+4)+15)=0



We calculate terms in parentheses: -(3(n+4)+15), so:

3(n+4)+15

We multiply parentheses

3n+12+15

We add all the numbers together, and all the variables

3n+27

Back to the equation:

-(3n+27)



We get rid of parentheses

2n-3n-27=0

We add all the numbers together, and all the variables

-1n-27=0

We move all terms containing n to the left, all other terms to the right

-n=27

n=27/-1

n=-27

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