2n=3+3/n

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Solution for 2n=3+3/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

2*n = 3/n+3 // - 3/n+3

2*n-(3/n)-3 = 0

2*n-3*n^-1-3 = 0

2*n^1-3*n^-1-3*n^0 = 0

(2*n^2-3*n^1-3*n^0)/(n^1) = 0 // * n^2

n^1*(2*n^2-3*n^1-3*n^0) = 0

n^1

2*n^2-3*n-3 = 0

2*n^2-3*n-3 = 0

DELTA = (-3)^2-(-3*2*4)

DELTA = 33

DELTA > 0

n = (33^(1/2)+3)/(2*2) or n = (3-33^(1/2))/(2*2)

n = (33^(1/2)+3)/4 or n = (3-33^(1/2))/4

n in { (3-33^(1/2))/4, (33^(1/2)+3)/4} 

n in { (3-33^(1/2))/4, (33^(1/2)+3)/4 }

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