2p(p-3)-3p(3p-2)=0

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Solution for 2p(p-3)-3p(3p-2)=0 equation: 



2p(p-3)-3p(3p-2)=0

We multiply parentheses

2p^2-9p^2-6p+6p=0

We add all the numbers together, and all the variables

-7p^2=0

a = -7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-7)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{-14}=0$

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