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2p(p-4)+9p(p-4)+9(p-4)=0
We multiply parentheses
2p^2+9p^2-8p-36p+9p-36=0
We add all the numbers together, and all the variables
11p^2-35p-36=0
a = 11; b = -35; c = -36;
Δ = b2-4ac
Δ = -352-4·11·(-36)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-53}{2*11}=\frac{-18}{22} =-9/11 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+53}{2*11}=\frac{88}{22} =4 $
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