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2p+1/p=5
We move all terms to the left:
2p+1/p-(5)=0
Domain of the equation: p!=0We multiply all the terms by the denominator
p∈R
2p*p-5*p+1=0
We add all the numbers together, and all the variables
-5p+2p*p+1=0
Wy multiply elements
2p^2-5p+1=0
a = 2; b = -5; c = +1;
Δ = b2-4ac
Δ = -52-4·2·1
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{17}}{2*2}=\frac{5-\sqrt{17}}{4} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{17}}{2*2}=\frac{5+\sqrt{17}}{4} $
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