2p-2(3-3p)=3(p-4)=9

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Solution for 2p-2(3-3p)=3(p-4)=9 equation:



2p-2(3-3p)=3(p-4)=9
We move all terms to the left:
2p-2(3-3p)-(3(p-4))=0
We add all the numbers together, and all the variables
2p-2(-3p+3)-(3(p-4))=0
We multiply parentheses
2p+6p-(3(p-4))-6=0
We calculate terms in parentheses: -(3(p-4)), so:
3(p-4)
We multiply parentheses
3p-12
Back to the equation:
-(3p-12)
We add all the numbers together, and all the variables
8p-(3p-12)-6=0
We get rid of parentheses
8p-3p+12-6=0
We add all the numbers together, and all the variables
5p+6=0
We move all terms containing p to the left, all other terms to the right
5p=-6
p=-6/5
p=-1+1/5

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