2p-3(3-3p)=6(p-6)-33

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Solution for 2p-3(3-3p)=6(p-6)-33 equation: 



2p-3(3-3p)=6(p-6)-33

We move all terms to the left:

2p-3(3-3p)-(6(p-6)-33)=0

We add all the numbers together, and all the variables

2p-3(-3p+3)-(6(p-6)-33)=0

We multiply parentheses

2p+9p-(6(p-6)-33)-9=0



We calculate terms in parentheses: -(6(p-6)-33), so:

6(p-6)-33

We multiply parentheses

6p-36-33

We add all the numbers together, and all the variables

6p-69

Back to the equation:

-(6p-69)



We add all the numbers together, and all the variables

11p-(6p-69)-9=0

We get rid of parentheses

11p-6p+69-9=0

We add all the numbers together, and all the variables

5p+60=0

We move all terms containing p to the left, all other terms to the right

5p=-60

p=-60/5

p=-12

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