2p-4(2-2p)=5(p-2)-28

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Solution for 2p-4(2-2p)=5(p-2)-28 equation: 



2p-4(2-2p)=5(p-2)-28

We move all terms to the left:

2p-4(2-2p)-(5(p-2)-28)=0

We add all the numbers together, and all the variables

2p-4(-2p+2)-(5(p-2)-28)=0

We multiply parentheses

2p+8p-(5(p-2)-28)-8=0



We calculate terms in parentheses: -(5(p-2)-28), so:

5(p-2)-28

We multiply parentheses

5p-10-28

We add all the numbers together, and all the variables

5p-38

Back to the equation:

-(5p-38)



We add all the numbers together, and all the variables

10p-(5p-38)-8=0

We get rid of parentheses

10p-5p+38-8=0

We add all the numbers together, and all the variables

5p+30=0

We move all terms containing p to the left, all other terms to the right

5p=-30

p=-30/5

p=-6

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