2p=p+4/9p=

Solution for 2p=p+4/9p= equation:

2p=p+4/9p=

We move all terms to the left:

2p-(p+4/9p)=0


Domain of the equation: 9p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

2p-(+p+4/9p)=0

We get rid of parentheses

2p-p-4/9p=0

We multiply all the terms by the denominator


2p*9p-p*9p-4=0

Wy multiply elements

18p^2-9p^2-4=0

We add all the numbers together, and all the variables

9p^2-4=0

a = 9; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·9·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*9}=\frac{-12}{18}
=-2/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*9}=\frac{12}{18}
=2/3
$