2q+28=2(5q-2)

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Solution for 2q+28=2(5q-2) equation:



2q+28=2(5q-2)
We move all terms to the left:
2q+28-(2(5q-2))=0
We calculate terms in parentheses: -(2(5q-2)), so:
2(5q-2)
We multiply parentheses
10q-4
Back to the equation:
-(10q-4)
We get rid of parentheses
2q-10q+4+28=0
We add all the numbers together, and all the variables
-8q+32=0
We move all terms containing q to the left, all other terms to the right
-8q=-32
q=-32/-8
q=+4

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