2q/3+5/q-q/6=5q/6-2/18

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Solution for 2q/3+5/q-q/6=5q/6-2/18 equation:


D( q )

q = 0

q = 0

q = 0

q in (-oo:0) U (0:+oo)

(2*q)/3-(q/6)+5/q = (5*q)/6-(2/18) // - (5*q)/6-(2/18)

(2*q)/3-(q/6)-((5*q)/6)+5/q+2/18 = 0

(2*q)/3-(q/6)+(-5/6)*q+5/q+2/18 = 0

5*q^-1-1/3*q^1+1/9*q^0 = 0

(1/9*q^1-1/3*q^2+5*q^0)/(q^1) = 0 // * q^2

q^1*(1/9*q^1-1/3*q^2+5*q^0) = 0

q^1

(-1/3)*q^2+(1/9)*q+5 = 0

(-1/3)*q^2+(1/9)*q+5 = 0

DELTA = (1/9)^2-(4*5*(-1/3))

DELTA = 541/81

DELTA > 0

q = ((541/81)^(1/2)-(1/9))/(2*(-1/3)) or q = (-(1/9)-(541/81)^(1/2))/(2*(-1/3))

q = -3/2*((541/81)^(1/2)-1/9) or q = 3/2*((541/81)^(1/2)+1/9)

q in { -3/2*((541/81)^(1/2)-1/9), 3/2*((541/81)^(1/2)+1/9)}

q in { -3/2*((541/81)^(1/2)-1/9), 3/2*((541/81)^(1/2)+1/9) }

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