2r(4-r)=15

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Solution for 2r(4-r)=15 equation: 



2r(4-r)=15

We move all terms to the left:

2r(4-r)-(15)=0

We add all the numbers together, and all the variables

2r(-1r+4)-15=0

We multiply parentheses

-2r^2+8r-15=0

a = -2; b = 8; c = -15;
Δ = b2-4ac
Δ = 82-4·(-2)·(-15)
Δ = -56
Delta is less than zero, so there is no solution for the equation

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