2r+(3r+4r)=(2r+3r)+4

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Solution for 2r+(3r+4r)=(2r+3r)+4 equation: 



2r+(3r+4r)=(2r+3r)+4

We move all terms to the left:

2r+(3r+4r)-((2r+3r)+4)=0

We add all the numbers together, and all the variables

2r+(+7r)-((+5r)+4)=0

We get rid of parentheses

2r+7r-((+5r)+4)=0



We calculate terms in parentheses: -((+5r)+4), so:

(+5r)+4

We get rid of parentheses

5r+4

Back to the equation:

-(5r+4)



We add all the numbers together, and all the variables

9r-(5r+4)=0

We get rid of parentheses

9r-5r-4=0

We add all the numbers together, and all the variables

4r-4=0

We move all terms containing r to the left, all other terms to the right

4r=4

r=4/4

r=1

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