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2r+1/2(2r-4)=2r-8
We move all terms to the left:
2r+1/2(2r-4)-(2r-8)=0
Domain of the equation: 2(2r-4)!=0We get rid of parentheses
r∈R
2r+1/2(2r-4)-2r+8=0
We multiply all the terms by the denominator
2r*2(2r-4)-2r*2(2r-4)+8*2(2r-4)+1=0
Wy multiply elements
4r^2(2-4r^2(2+16r(2+1=0
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