2r+12(19)=8(5r-1)

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Solution for 2r+12(19)=8(5r-1) equation: 



2r+12(19)=8(5r-1)

We move all terms to the left:

2r+12(19)-(8(5r-1))=0



We calculate terms in parentheses: -(8(5r-1)), so:

8(5r-1)

We multiply parentheses

40r-8

Back to the equation:

-(40r-8)



We get rid of parentheses

2r-40r+8+1219=0

We add all the numbers together, and all the variables

-38r+1227=0

We move all terms containing r to the left, all other terms to the right

-38r=-1227

r=-1227/-38

r=32+11/38

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