2r+3(4r-1)=7(2r+4)

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Solution for 2r+3(4r-1)=7(2r+4) equation: 



2r+3(4r-1)=7(2r+4)

We move all terms to the left:

2r+3(4r-1)-(7(2r+4))=0

We multiply parentheses

2r+12r-(7(2r+4))-3=0



We calculate terms in parentheses: -(7(2r+4)), so:

7(2r+4)

We multiply parentheses

14r+28

Back to the equation:

-(14r+28)



We add all the numbers together, and all the variables

14r-(14r+28)-3=0

We get rid of parentheses

14r-14r-28-3=0

We add all the numbers together, and all the variables

-31!=0

There is no solution for this equation

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