2r+3(r+3)+r=1

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Solution for 2r+3(r+3)+r=1 equation: 



2r+3(r+3)+r=1

We move all terms to the left:

2r+3(r+3)+r-(1)=0

We add all the numbers together, and all the variables

3r+3(r+3)-1=0

We multiply parentheses

3r+3r+9-1=0

We add all the numbers together, and all the variables

6r+8=0

We move all terms containing r to the left, all other terms to the right

6r=-8

r=-8/6

r=-1+1/3

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