2r+3s=13;4r+7s=37

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Solution for 2r+3s=13;4r+7s=37 system of equations: 


  • /| 2*r+3*s-13 = 0| 4*r+7*s-37 = 0
  • We try to solve the equation: 2*r+3*s-13 = 0
  • 2*r+3*s-13 = 0 // - 2*r-13
  • 3*s = -(2*r-13) // : 3
  • s = (-(2*r-13))/3
  • s = (13-(2*r))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 7*((13-(2*r))/3)+4*r-37 = 0| s = (13-(2*r))/3
  • (7*(13-2*r))/3+4*r-37 = 0
  • 91/3-2/3*r-37 = 0
  • -2/3*r-20/3 = 0
  • -2/3*r-20/3 = 0 // + 20/3
  • -2/3*r = 20/3 // : -2/3
  • r = 20/3/(-2/3)
  • r = -10
  • We insert the solution into one of the initial equations of our system of equations
  • For s = (13-(2*r))/3: 
  • s = (13-(-10*2))/3
  • s = (13+20)/3
  • s = 33/3
  • s = 11
  • We get a system of equations:
  • /| s = 11| r = -10

 

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