2r+3u=2(3r+6)

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Solution for 2r+3u=2(3r+6) equation:


Simplifying
2r + 3u = 2(3r + 6)

Reorder the terms:
2r + 3u = 2(6 + 3r)
2r + 3u = (6 * 2 + 3r * 2)
2r + 3u = (12 + 6r)

Solving
2r + 3u = 12 + 6r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-6r' to each side of the equation.
2r + -6r + 3u = 12 + 6r + -6r

Combine like terms: 2r + -6r = -4r
-4r + 3u = 12 + 6r + -6r

Combine like terms: 6r + -6r = 0
-4r + 3u = 12 + 0
-4r + 3u = 12

Add '-3u' to each side of the equation.
-4r + 3u + -3u = 12 + -3u

Combine like terms: 3u + -3u = 0
-4r + 0 = 12 + -3u
-4r = 12 + -3u

Divide each side by '-4'.
r = -3 + 0.75u

Simplifying
r = -3 + 0.75u

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