2r+5+3+8r=-3(1-5r)-5(r-4)

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Solution for 2r+5+3+8r=-3(1-5r)-5(r-4) equation: 



2r+5+3+8r=-3(1-5r)-5(r-4)

We move all terms to the left:

2r+5+3+8r-(-3(1-5r)-5(r-4))=0

We add all the numbers together, and all the variables

2r+8r-(-3(-5r+1)-5(r-4))+5+3=0

We add all the numbers together, and all the variables

10r-(-3(-5r+1)-5(r-4))+8=0



We calculate terms in parentheses: -(-3(-5r+1)-5(r-4)), so:

-3(-5r+1)-5(r-4)

We multiply parentheses

15r-5r-3+20

We add all the numbers together, and all the variables

10r+17

Back to the equation:

-(10r+17)



We get rid of parentheses

10r-10r-17+8=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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