2r+6-5r=-3(r-2)

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Solution for 2r+6-5r=-3(r-2) equation: 



2r+6-5r=-3(r-2)

We move all terms to the left:

2r+6-5r-(-3(r-2))=0

We add all the numbers together, and all the variables

-3r-(-3(r-2))+6=0



We calculate terms in parentheses: -(-3(r-2)), so:

-3(r-2)

We multiply parentheses

-3r+6

Back to the equation:

-(-3r+6)



We get rid of parentheses

-3r+3r-6+6=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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