2r+6=2(2r-r)

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Solution for 2r+6=2(2r-r) equation: 



2r+6=2(2r-r)

We move all terms to the left:

2r+6-(2(2r-r))=0

We add all the numbers together, and all the variables

2r-(2(+r))+6=0



We calculate terms in parentheses: -(2(+r)), so:

2(+r)

We multiply parentheses

2r

Back to the equation:

-(2r)



We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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