2r-(9r+4)=(18r+8)+4r-(9r+4)+2r

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Solution for 2r-(9r+4)=(18r+8)+4r-(9r+4)+2r equation:



2r-(9r+4)=(18r+8)+4r-(9r+4)+2r
We move all terms to the left:
2r-(9r+4)-((18r+8)+4r-(9r+4)+2r)=0
We get rid of parentheses
2r-9r-((18r+8)+4r-(9r+4)+2r)-4=0
We calculate terms in parentheses: -((18r+8)+4r-(9r+4)+2r), so:
(18r+8)+4r-(9r+4)+2r
We add all the numbers together, and all the variables
6r+(18r+8)-(9r+4)
We get rid of parentheses
6r+18r-9r+8-4
We add all the numbers together, and all the variables
15r+4
Back to the equation:
-(15r+4)
We add all the numbers together, and all the variables
-7r-(15r+4)-4=0
We get rid of parentheses
-7r-15r-4-4=0
We add all the numbers together, and all the variables
-22r-8=0
We move all terms containing r to the left, all other terms to the right
-22r=8
r=8/-22
r=-4/11

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