2r-(9r+4)=(18r+8)+4r-(9r+4)+2r

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Solution for 2r-(9r+4)=(18r+8)+4r-(9r+4)+2r equation: 



2r-(9r+4)=(18r+8)+4r-(9r+4)+2r

We move all terms to the left:

2r-(9r+4)-((18r+8)+4r-(9r+4)+2r)=0

We get rid of parentheses

2r-9r-((18r+8)+4r-(9r+4)+2r)-4=0



We calculate terms in parentheses: -((18r+8)+4r-(9r+4)+2r), so:

(18r+8)+4r-(9r+4)+2r

We add all the numbers together, and all the variables

6r+(18r+8)-(9r+4)

We get rid of parentheses

6r+18r-9r+8-4

We add all the numbers together, and all the variables

15r+4

Back to the equation:

-(15r+4)



We add all the numbers together, and all the variables

-7r-(15r+4)-4=0

We get rid of parentheses

-7r-15r-4-4=0

We add all the numbers together, and all the variables

-22r-8=0

We move all terms containing r to the left, all other terms to the right

-22r=8

r=8/-22

r=-4/11

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