2r-2+2(r-4)=2(r+6)

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Solution for 2r-2+2(r-4)=2(r+6) equation:


Simplifying
2r + -2 + 2(r + -4) = 2(r + 6)

Reorder the terms:
2r + -2 + 2(-4 + r) = 2(r + 6)
2r + -2 + (-4 * 2 + r * 2) = 2(r + 6)
2r + -2 + (-8 + 2r) = 2(r + 6)

Reorder the terms:
-2 + -8 + 2r + 2r = 2(r + 6)

Combine like terms: -2 + -8 = -10
-10 + 2r + 2r = 2(r + 6)

Combine like terms: 2r + 2r = 4r
-10 + 4r = 2(r + 6)

Reorder the terms:
-10 + 4r = 2(6 + r)
-10 + 4r = (6 * 2 + r * 2)
-10 + 4r = (12 + 2r)

Solving
-10 + 4r = 12 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
-10 + 4r + -2r = 12 + 2r + -2r

Combine like terms: 4r + -2r = 2r
-10 + 2r = 12 + 2r + -2r

Combine like terms: 2r + -2r = 0
-10 + 2r = 12 + 0
-10 + 2r = 12

Add '10' to each side of the equation.
-10 + 10 + 2r = 12 + 10

Combine like terms: -10 + 10 = 0
0 + 2r = 12 + 10
2r = 12 + 10

Combine like terms: 12 + 10 = 22
2r = 22

Divide each side by '2'.
r = 11

Simplifying
r = 11

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