2r-263=5(-9r-7)+9r

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Solution for 2r-263=5(-9r-7)+9r equation: 



2r-263=5(-9r-7)+9r

We move all terms to the left:

2r-263-(5(-9r-7)+9r)=0



We calculate terms in parentheses: -(5(-9r-7)+9r), so:

5(-9r-7)+9r

We add all the numbers together, and all the variables

9r+5(-9r-7)

We multiply parentheses

9r-45r-35

We add all the numbers together, and all the variables

-36r-35

Back to the equation:

-(-36r-35)



We get rid of parentheses

2r+36r+35-263=0

We add all the numbers together, and all the variables

38r-228=0

We move all terms containing r to the left, all other terms to the right

38r=228

r=228/38

r=6

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