2r-5(z+2)=-8-2z

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Solution for 2r-5(z+2)=-8-2z equation:


Simplifying
2r + -5(z + 2) = -8 + -2z

Reorder the terms:
2r + -5(2 + z) = -8 + -2z
2r + (2 * -5 + z * -5) = -8 + -2z
2r + (-10 + -5z) = -8 + -2z

Reorder the terms:
-10 + 2r + -5z = -8 + -2z

Solving
-10 + 2r + -5z = -8 + -2z

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 2r + 10 + -5z = -8 + 10 + -2z

Reorder the terms:
-10 + 10 + 2r + -5z = -8 + 10 + -2z

Combine like terms: -10 + 10 = 0
0 + 2r + -5z = -8 + 10 + -2z
2r + -5z = -8 + 10 + -2z

Combine like terms: -8 + 10 = 2
2r + -5z = 2 + -2z

Add '5z' to each side of the equation.
2r + -5z + 5z = 2 + -2z + 5z

Combine like terms: -5z + 5z = 0
2r + 0 = 2 + -2z + 5z
2r = 2 + -2z + 5z

Combine like terms: -2z + 5z = 3z
2r = 2 + 3z

Divide each side by '2'.
r = 1 + 1.5z

Simplifying
r = 1 + 1.5z

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