2r-6+5r=3-5(r-7)

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Solution for 2r-6+5r=3-5(r-7) equation: 



2r-6+5r=3-5(r-7)

We move all terms to the left:

2r-6+5r-(3-5(r-7))=0

We add all the numbers together, and all the variables

7r-(3-5(r-7))-6=0



We calculate terms in parentheses: -(3-5(r-7)), so:

3-5(r-7)

determiningTheFunctionDomain
-5(r-7)+3

We multiply parentheses

-5r+35+3

We add all the numbers together, and all the variables

-5r+38

Back to the equation:

-(-5r+38)



We get rid of parentheses

7r+5r-38-6=0

We add all the numbers together, and all the variables

12r-44=0

We move all terms containing r to the left, all other terms to the right

12r=44

r=44/12

r=3+2/3

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