2r-8/r=r-4/8

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Solution for 2r-8/r=r-4/8 equation: 


D( r )

r = 0

r = 0

r = 0

r in (-oo:0) U (0:+oo)

2*r-(8/r) = r-(4/8) // - r-(4/8)

2*r-r-(8/r)+4/8 = 0

2*r-r-8*r^-1+4/8 = 0

1*r^1-8*r^-1+1/2*r^0 = 0

(1*r^2+1/2*r^1-8*r^0)/(r^1) = 0 // * r^2

r^1*(1*r^2+1/2*r^1-8*r^0) = 0

r^1

r^2+(1/2)*r-8 = 0

r^2+(1/2)*r-8 = 0

DELTA = (1/2)^2-(-8*1*4)

DELTA = 129/4

DELTA > 0

r = ((129/4)^(1/2)-(1/2))/(1*2) or r = (-(1/2)-(129/4)^(1/2))/(1*2)

r = ((129/4)^(1/2)-1/2)/2 or r = (-((129/4)^(1/2)+1/2))/2

r in { (-((129/4)^(1/2)+1/2))/2, ((129/4)^(1/2)-1/2)/2} 

r in { (-((129/4)^(1/2)+1/2))/2, ((129/4)^(1/2)-1/2)/2 }

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