2r/9=9/(2r-3)

Solution for 2r/9=9/(2r-3) equation:

2r/9=9/(2r-3)

We move all terms to the left:

2r/9-(9/(2r-3))=0


Domain of the equation: (2r-3))!=0

r∈R


We calculate fractions


(-2r^2)/18r+()/18r=0

We multiply all the terms by the denominator


(-2r^2)+()=0

We add all the numbers together, and all the variables

(-2r^2)=0

We get rid of parentheses

-2r^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-4}=0$