2r=3(1+r)+18

Solution for 2r=3(1+r)+18 equation:

2r=3(1+r)+18

We move all terms to the left:

2r-(3(1+r)+18)=0

We add all the numbers together, and all the variables

2r-(3(r+1)+18)=0


We calculate terms in parentheses: -(3(r+1)+18), so:

3(r+1)+18

We multiply parentheses

3r+3+18

We add all the numbers together, and all the variables

3r+21

Back to the equation:

-(3r+21)


We get rid of parentheses

2r-3r-21=0

We add all the numbers together, and all the variables

-1r-21=0

We move all terms containing r to the left, all other terms to the right

-r=21

r=21/-1

r=-21